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📅 February 28, 2026 👤 scraface

Feb 28, 2026

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Vereinfache: \( 20 = \frac{100}{\pi a} \).
Löse nach \( a \): \( a = \frac{100}{20 \pi} = \frac{5}{\pi} \approx 1...
#### 1.5915
### Frage 9
Ein Materialwissenschaftler untersucht die Wärmeleitfähigkeit \( k \)...
Berechne \( k_1 d_1 = 200 \times 2 = 400 \).
Berechne \( k_2 d_2^2 = 50 \times 1^2 = 50 \).
Zähler: \( 400 + 50 = 450 \).
Nenner: \( 2 + 1 = 3 \).
Also \( k = \frac{450}{3} = 150 \) W/m·K.

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