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📅 February 28, 2026 👤 scraface

Feb 28, 2026

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\text{Diagonal} = 2R = 10 \text{ cm}
For a square with side $ s $, the diagonal is $ s\sqrt{2} $. Therefore...
s\sqrt{2} = 10 \Rightarrow s = \frac{10}{\sqrt{2}} = 5\sqrt{2}
The area of the square is:
s^2 = (5\sqrt{2})^2 = 25 \cdot 2 = 50
Thus, the area is $ \boxed{50} $.
Question: An equilateral triangle has an area of $ 36\sqrt{3} $ cm². I...
The area $ A $ of an equilateral triangle with side length $ s $ is:
A = \frac{\sqrt{3}}{4} s^2
Given $ \frac{\sqrt{3}}{4} s^2 = 36\sqrt{3} $, divide both sides by $...

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