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Home » Secret Technique Revealed: How to Draw a Stunning Lighthouse Perfectly Every Time! - Upplift

Secret Technique Revealed: How to Draw a Stunning Lighthouse Perfectly Every Time! - Upplift

📅 February 28, 2026 👤 scraface

Feb 28, 2026

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📌 But to allow full batch deployment, $ B $ must *divide* some $ D $ divisible by 9 in [100,199].

📌 So the condition is: $ B $ divides some $ D $ with $ D \in [100,199] $, $ 9 \mid D $

📌 But since $ D $ must be divisible by 9, and $ B \mid D $, $ B $ must be such that it divides at least one multiple of 9 in the range.

📌 But every multiple of 11 could divide such a $ D $, but we want the smallest $ B \equiv 0 \pmod{11} $ such that $ B \mid D $ for some $ D \in [100,199] $, $ 9 \mid D $

📌 But actually, we just need that $ B $ divides some multiple of 9 in that interval â which is always possible unless $ B $ is too large.

📌 But actually, the real constraint is: for the model to process full batches, $ B $ must divide $ D $, and $ D $ divisible by 9. So $ B $ must divide a multiple of 9. But every integer divides some multiple of 9 (e.g., $ D = B \cdot 9 $, but we require $ B $ divisible by 11).

📌 Better approach: we are to find the smallest $ B $ divisible by 11 such that $ B $ divides some $ D \in [100,199] $ with $ 9 \mid D $.

📌 But since $ D $ must be divisible by 9, we list all multiples of 9 in [100,199]:

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Assume radius r = 0.1 m (typical for small welds).
Then per turn: path length = \( \sqrt{(2\pi \times 0.1)^2 + 1^2} = \sq...
Total for 6 turns: \( 6 \times 1.181 \approx 7.086 \) m.
Time = \( \frac{1.5}{0.5} = 3 \) seconds.
But too messy.
Alternative: drop radius, but use only linear projection? No.
Better narrative:
A robotic arm welds a pipe using a helical motion with a fixed pitch o...
But not aligned.
New idea:

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