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Home » Thus, the ratio is \(\boxed\frac1k^3\). - Upplift

Thus, the ratio is \(\boxed\frac1k^3\). - Upplift

📅 February 27, 2026 👤 scraface

Feb 27, 2026

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Total number of valid paths: arrange 4 F’s and 3 R’s →
\text{Total paths} = \binom{7}{4} = 35
Now, fix the first move as F and the last move as R.
That leaves us with: 3 F’s and 2 R’s to arrange in the middle 5 positi...
Number of such favorable paths:
\binom{5}{3} = 10
\frac{10}{35} = \frac{2}{7}
Hence, the probability is $ \boxed{\frac{2}{7}} $.
Question: A data scientist trains a model using sequences of 5 binary...
This is a binomial probability with $ n = 5 $, $ k = 3 $, and success...

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