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what is half of 1/4th cup - Upplift

📅 February 28, 2026 👤 scraface

Feb 28, 2026

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To find the area of the region enclosed by the curves \( y = x^2 \) an...
x^2 = 4x - x^2.
2x^2 - 4x = 0.
Factoring out \( 2x \):
2x(x - 2) = 0.
Thus, the points of intersection are \( x = 0 \) and \( x = 2 \).
The area \( A \) between the curves from \( x = 0 \) to \( x = 2 \) is...
A = \int_0^2 \left((4x - x^2) - x^2\right) \, dx = \int_0^2 (4x - 2x^2...
Evaluating the integral:
A = \left[ 2x^2 - \frac{2}{3}x^3 \right]_0^2 = \left( 2(2)^2 - \frac{2...

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