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Home » You Won’t Believe What Telekinetic Powers Can Actually Do—Science Confirms It! - Upplift

You Won’t Believe What Telekinetic Powers Can Actually Do—Science Confirms It! - Upplift

📅 February 28, 2026 👤 scraface

Feb 28, 2026

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📌 Solve for \( x^2 \):

📌 \[ x^2 = 8 + 4 = 12 \Rightarrow x = \pm \sqrt{12} = \pm 2\sqrt{3}. \]

📌 Since the argument of a logarithm must be positive and \( x^2 - 4 = 8 > 0 \), both values are valid. However, the equation is satisfied by both. Since the question asks for *the* value, and no restriction on sign is given, we present the positive solution as standard unless otherwise specified. But both are mathematically correct. To match typical expectations, we provide the positive root.

📌 Thus, one solution is \( \boxed{2\sqrt{3}} \).

📌 Clarification Note:** Since \( \log_2(x^2 - 4) = 3 \) requires \( x^2 - 4 > 0 \Rightarrow x^2 > 4 \Rightarrow |x| > 2 \), both \( \pm 2\sqrt{3} \approx \pm 3.464 \) satisfy this. However, the equation yields \( x^2 = 12 \), so both roots are valid. Depending on context, both may be acceptable. For a single boxed answer, we list the positive one:

📌 \boxed{2\sqrt{3}}

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So \( r = \frac{0.4699}{6} \approx 0.0783 \) → 7.83%
Rounded to nearest percent: 8%
But check: 500 × e^(0.0783×6) ≈ 500 × e^0.4698 ≈ 500 × 1.600 = 800 → c...
So 7.83% → closest whole percent is 8%
But answer should be approximate — use 8%
However, math: 0.0783 → 7.83%, but in context, often reported as 8%
\( r = \frac{\ln(1.6)}{6} \approx \frac{0.4700}{6} \approx 0.07833 \)...
A palynologist finds that the ratio of birch to pine pollen halves eve...
Let ratio \( R(t) = R_0 \cdot (0.5)^{t/150} \)
Set \( R(t) = 1/16 \), \( R_0 = 1 \) (since 1:16 corresponds to \( R(0...

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